0=2r^2-19r

Solution for 0=2r^2-19r equation:

0=2r^2-19r

We move all terms to the left:

0-(2r^2-19r)=0

We add all the numbers together, and all the variables

-(2r^2-19r)=0

We get rid of parentheses

-2r^2+19r=0

a = -2; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-2)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-2}=\frac{-38}{-4}
=9+1/2
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-2}=\frac{0}{-4}
=0
$